This is because a basis requires a Set of Linearly IndepedentVectors, and does not meet this requirement. Therefore, its only basis is . The cardinality of the empty set is 0, therefore so is
Examples
dim
dim(Nul A) is the number of
number of free vars of A
dim(Col A) is the number of
number of pivots of A
H =
n variables, solve for ito everything else. → one pivot everything else free vars. Therefore free vars