The dimension of a Subspace is the Cardinality of its Basis

This is because a basis requires a Set of Linearly Indepedent Vectors, and does not meet this requirement. Therefore, its only basis is . The cardinality of the empty set is 0, therefore so is

Examples

  • dim
  • dim(Nul A) is the number of
    • number of free vars of A
  • dim(Col A) is the number of
    • number of pivots of A
  • H =
    • n variables, solve for ito everything else. one pivot everything else free vars. Therefore free vars