The dimension of a Subspace
This is because a basis requires a Set of Linearly Indepedent Vectors, and
does not meet this requirement. Therefore, its only basis is . The cardinality of the empty set is 0, therefore so is
Examples
- dim
- dim(Nul A) is the number of
- number of free vars of A
- dim(Col A) is the number of
- number of pivots of A
- H =
- n variables, solve for
ito everything else. → one pivot everything else free vars. Therefore free vars
- n variables, solve for