Assume the elements before the current index are sorted. Insert the next element in the remaining dataset into the correct place in the sorted data.
Iterative Sorts are generally bad unless the data set is relatively small

Evaluation
Pseudocode
for n in [1, arr.length) {
for i = n; i > 0 and arr[i] < arr[i - 1]; i-- {
swapAt(i, i - 1)
}
}