Analysis
| Best Case | Worst Case | |
|---|---|---|
| No occurrences | ||
| Single occurence | ||
| All Occurencess |
Pseudocode
bruteforce(text, pattern) {
n = len(text)
m = len(pattern)
for n length substring in text from left to right {
if current substring matches pattern { return current index }
}
return pattern not found
}